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WB JEE Medical WB JEE Medical Solved Paper-2006

  • question_answer
    The volume of oxygen necessary for the complete combustion of 20 L of propane is :

    A)  40 L                                      

    B)  60 L

    C)  80 L                                      

    D)  100 L

    Correct Answer: D

    Solution :

                     Combustion of propane takes place as follows: \[\underset{\text{Propane}}{\mathop{{{C}_{3}}{{H}_{8}}}}\,+\underset{\text{Oxygen}}{\mathop{5{{O}_{2}}}}\,\xrightarrow{{}}3C{{O}_{2}}+4{{H}_{2}}O\] \[\because \] 1 L of propane required 5L of oxygen for combustion. \[\therefore \] 20 L of propane required oxygen \[=\text{ }5\times 20\text{ }=100\text{ }L.\]


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