A) \[\frac{r}{4}\]
B) \[\frac{r}{2}\]
C) \[2r\]
D) \[4r\]
Correct Answer: D
Solution :
In a perpendicular magnetic field, Magnetic force = centripetal force i.e., \[Bqv=\frac{m{{v}^{2}}}{r}\] \[\Rightarrow \] \[r=\frac{mv}{Br}\] \[\Rightarrow \]\[r\propto {{v}^{2}}\] \[\therefore \] \[\frac{{{r}_{2}}}{r}=\frac{v_{2}^{2}}{v_{1}^{2}}={{\left( \frac{2v}{v} \right)}^{2}}=4\] \[\Rightarrow \] \[{{r}_{2}}=4r\]You need to login to perform this action.
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