A) 10 V
B) 20 V
C) 35 V
D) 70 V
Correct Answer: C
Solution :
Given, \[\text{o }\!\!|\!\!\text{ =}\,\text{5}{{\text{t}}^{2}}-100t+300\] \[\therefore \] \[e=-\frac{d\text{o }\!\!|\!\!\text{ }}{dt}\] \[=\frac{-d}{dt}(5{{t}^{3}}-100t+300)\] \[=-(15{{t}^{2}}-100+0)\] \[=-15{{t}^{2}}+100\] \[\therefore \] \[\frac{e}{t}=-15{{(3)}^{2}}+100\] \[=-15\times 9+100\] \[=-135+100\] \[=-35\,V\] Minus sign signifies the Lenzs law.You need to login to perform this action.
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