A) 40 L
B) 60 L
C) 80 L
D) 100 L
Correct Answer: D
Solution :
Combustion of propane takes place as follows: \[\underset{\text{Propane}}{\mathop{{{C}_{3}}{{H}_{8}}}}\,+\underset{\text{Oxygen}}{\mathop{5{{O}_{2}}}}\,\xrightarrow{{}}3C{{O}_{2}}+4{{H}_{2}}O\] \[\because \] 1 L of propane required 5L of oxygen for combustion. \[\therefore \] 20 L of propane required oxygen \[=\text{ }5\times 20\text{ }=100\text{ }L.\]You need to login to perform this action.
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