A) \[{{\,}_{\text{89}}}\text{A}{{\text{c}}^{225}}\]
B) \[{{\,}_{\text{90}}}T{{h}^{232}}\]
C) \[{{\,}_{15}}T{{h}^{35}}\]
D) \[{{\,}_{92}}{{U}^{235}}\]
Correct Answer: D
Solution :
The series \[4n+3\] is known as actinium series. It shows that if mass number is divided by 4 then the remainder must be 3. Hence, the another member of this series is \[{{\,}_{92}}{{U}^{235}}.\] \[\because \] \[\frac{235}{4}=58+\text{Remainder}\,\text{3}\]
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