A) 75 aim
B) 160 atm
C) 180 atm
D) 215 atm
Correct Answer: C
Solution :
First of all we have to calculate the number of moles. Number of moles of \[{{N}_{2}}=\frac{56}{28}=2\] Number of moles of \[C{{O}_{2}}=\frac{44}{44}=1\] Number of moles of \[C{{H}_{4}}=\frac{16}{16}=1\] \[\therefore \]Total number of moles \[=2+1+1=4\] \[\therefore \] mole fraction of \[C{{H}_{4}}=\frac{1}{4}\] \[\therefore \] partial pressure of \[C{{H}_{4}}\] = mole fraction of \[C{{H}_{4}}\times \]total pressure \[=\frac{1}{4}\times 720=180\,\text{atm}\]You need to login to perform this action.
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