A) \[FeS{{O}_{4}}.NO\]
B) \[[Fe{{(S{{O}_{4}})}_{2}}.NO]{{H}_{2}}O\]
C) \[F{{e}_{2}}{{(S{{O}_{4}})}_{3}}.NO\]
D) none of these
Correct Answer: A
Solution :
Brown ring in the ring-test of \[\text{NO}_{3}^{-}\] is formed due to the formation of \[FeS{{O}_{4}}.NO\] at the junction of two liquids.You need to login to perform this action.
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