A) \[1\,\text{m}{{\text{s}}^{-1}}\]
B) \[2\,\text{m}{{\text{s}}^{-1}}\]
C) \[1.5\,\text{m}{{\text{s}}^{-1}}\]
D) \[1.25\,\text{m}{{\text{s}}^{-1}}\]
Correct Answer: D
Solution :
Equation of wave \[y=5\sin \left( \frac{t}{0.04}-\frac{x}{4} \right)\] The standard equation of a wave in the given form is \[y=a\,\sin \left( \omega t-\frac{2\pi \,x}{\lambda } \right)\] Comparing the given equation with the standard equation, we get \[a=5\]and \[\omega =\frac{1}{0.04}=25\] Therefore, maximum velocity of particles of the medium, \[{{v}_{\max }}=a\omega \] \[=5\times 25\] \[=125\,cm{{s}^{-1}}=1.25\,m{{s}^{-1}}\]
You need to login to perform this action.
You will be redirected in
3 sec
