WB JEE Medical WB JEE Medical Solved Paper-2006

  • question_answer
    A black body has a wavelength of\[\lambda \] at temperature  2000 K.   Its  corresponding wavelength at temperature 3000 K will be :

    A)  \[\frac{2\lambda }{3}\]                                

    B)  \[\frac{3\lambda }{2}\]

    C)  \[\frac{4\lambda }{9}\]                                

    D)  \[\frac{9\lambda }{4}\]

    Correct Answer: A

    Solution :

                     According to Wiens displacement law \[{{\lambda }_{m}}T=\operatorname{constant}\] or            \[\frac{{{\lambda }_{2}}}{{{\lambda }_{1}}}=\frac{{{T}_{1}}}{{{T}_{2}}}\] \[\therefore \]  \[\frac{{{\lambda }_{2}}}{\lambda }=\frac{2000}{3000}=\frac{2}{3}\] or            \[{{\lambda }_{2}}=\frac{2}{3}\lambda \]


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