WB JEE Medical WB JEE Medical Solved Paper-2006

  • question_answer
    Ten moles of an ideal gas at constant temperature 500 K is compressed from 50 L to 5 L. Work done in the process is (Given, \[R=8.31\,J-mo{{l}^{-1}}-{{K}^{-1}}\]) :

    A)  \[-1.2\times {{10}^{4}}J\]                           

    B)  \[-2.4\times {{10}^{4}}J\]

    C)  \[-\,4.8\times {{10}^{4}}J\]                        

    D)  \[-\,9.6\times {{10}^{4}}J\]

    Correct Answer: D

    Solution :

                     Work done at constant temperature (i.e., isothermal process), \[W=2.3nRT\,{{\log }_{10}}\left( \frac{{{v}_{2}}}{{{v}_{1}}} \right)\] \[=2.3\times 10\times 8.31\times 500\times {{\log }_{10}}\left( \frac{5}{50} \right)\] \[=-9.6\times {{10}^{4}}J\]


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