WB JEE Medical WB JEE Medical Solved Paper-2006

  • question_answer
    Two coherent light beams of intensity \[I\] and \[4I\]are superposed. The maximum and minimum possible intensities in the resulting beam are :

    A)  \[5I\]and \[I\]                  

    B)  \[5I\]and\[3I\]

    C)  \[9I\] and \[I\]                 

    D)  \[9I\]and \[3I\]

    Correct Answer: C

    Solution :

                     Given, \[{{I}_{1}}=I,{{I}_{2}}=4I\] \[{{I}_{\max }}={{(\sqrt{{{I}_{1}}}+\sqrt{{{I}_{2}}})}^{2}}\] \[={{(\sqrt{I}+\sqrt{4I})}^{2}}={{(3\sqrt{I})}^{2}}=9I\] \[{{I}_{\min }}={{(\sqrt{{{I}_{1}}}-\sqrt{{{I}_{2}}})}^{2}}\] \[={{(\sqrt{I}-\sqrt{4I})}^{2}}\] \[={{(-\sqrt{I})}^{2}}\] \[=I\]


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