A) 2F
B) 4F
C) \[\frac{F}{2}\]
D) \[\frac{F}{4}\]
Correct Answer: D
Solution :
\[{{F}_{i}}=\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{{{q}_{1}}{{q}_{2}}}{{{d}^{2}}}\] ?(i) \[{{F}_{f}}=\frac{1}{4\pi {{\varepsilon }_{0}}k}\frac{{{q}_{1}}{{q}_{2}}}{{{d}^{2}}}\] or \[{{F}_{f}}=\frac{1}{4}\left( \frac{1}{4\pi {{\varepsilon }_{0}}}\frac{{{q}_{1}}{{q}_{2}}}{{{d}^{2}}} \right)=\frac{1}{4}F\](from Eq.(i))
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