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WB JEE Medical WB JEE Medical Solved Paper-2006

  • question_answer
    The ratio of voltage sensitivity \[({{V}_{S}})\] and current sensitivity \[({{I}_{S}})\] of a moving coil galvanometers:

    A)  \[\frac{1}{G}\]                                 

    B)  \[\frac{1}{{{G}^{2}}}\]

    C)  \[G\]                                   

    D)  \[{{G}^{2}}\]

    Correct Answer: A

    Solution :

                     Voltage sensitivity \[=\frac{Q}{V}\] Current sensitivity \[=\frac{Q}{I}\] Also, potential difference, \[V=IG\]                 Hence, \[\frac{{{V}_{S}}}{{{I}_{S}}}=\frac{Q/V}{Q/I}=\frac{I}{V}=\frac{I}{IG}\]                 \[\therefore \]  \[\frac{{{V}_{S}}}{{{I}_{S}}}=\frac{1}{G}\]


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