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WB JEE Medical WB JEE Medical Solved Paper-2006

  • question_answer
    In 0.1 s, the current in a coil increases from 1 A to 1.5 A. If inductance of coil is 60 mH, then induced current in external resistance of \[3\Omega \]will be :

    A)  1 A                                        

    B)  0.5 A

    C)  0.2A                                     

    D)  0.1A

    Correct Answer: D

    Solution :

                     Induced emf, \[|e|=L\frac{di}{dt}\] \[=(60\times {{10}^{-3}})\times \frac{(1.5-1)}{0.1}\]                 \[=\frac{60\times {{10}^{-3}}\times 0.5}{0.1}=0.3\,V\] Induced current, \[i=\frac{e}{R}=\frac{0.3}{3}=0.1A\]


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