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WB JEE Medical WB JEE Medical Solved Paper-2006

  • question_answer
    The impedance of a circuit, when a resistance R and an inductor of inductance L are connected in series in an AC circuit of frequency \[f,\] is :

    A)  \[\sqrt{R+2{{\pi }^{2}}{{f}^{2}}{{L}^{2}}}\]

    B)  \[\sqrt{R+4{{\pi }^{2}}{{f}^{2}}{{L}^{2}}}\]

    C)  \[\sqrt{{{R}^{2}}+4{{\pi }^{2}}{{f}^{2}}{{L}^{2}}}\]

    D)  \[\sqrt{{{R}^{2}}+2{{\pi }^{2}}{{f}^{2}}{{L}^{2}}}\]

    Correct Answer: B

    Solution :

                     In L-R circuit, impedance \[Z=\sqrt{{{R}^{2}}+X_{L}^{2}}\] Here,     \[{{X}_{L}}=\omega L=2\pi \,fL\] \[\therefore \]  \[Z=\sqrt{{{R}^{2}}+4{{\pi }^{2}}{{f}^{2}}{{L}^{2}}}\]


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