WB JEE Medical WB JEE Medical Solved Paper-2006

  • question_answer
    In a series LCR circuit, resistance \[R=10\,\Omega \]and the impedance \[Z=10\,\Omega .\]The phase difference between the current and the voltage is :

    A) \[{{\text{0}}^{\text{o}}}\]                                           

    B)  \[\text{3}{{\text{0}}^{\text{o}}}\]

    C) \[{{45}^{\text{o}}}\]                                      

    D)  \[{{60}^{\text{o}}}\]

    Correct Answer: A

    Solution :

                     Impedance, \[Z=\sqrt{{{R}^{2}}+{{({{X}_{L}}-{{X}_{C}})}^{2}}}\] \[\therefore \]  \[10=\sqrt{{{(10)}^{2}}+{{({{X}_{L}}-{{X}_{C}})}^{2}}}\] \[\Rightarrow \]               \[100=100+{{({{X}_{L}}-{{X}_{C}})}^{2}}\] \[\Rightarrow \]               \[{{X}_{L}}-{{X}_{C}}=0\] Let \[\text{o }\!\!|\!\!\text{ }\] is the phase difference between current and voltage \[\tan =\text{o }\!\!|\!\!\text{ =}\frac{{{X}_{L}}-{{X}_{C}}}{R}\]                 \[\therefore \]  \[\tan \,o|=\frac{0}{R}\]                 \[\Rightarrow \]               \[\text{o }\!\!|\!\!\text{ =}\,\text{0}\]                                  [from Eq (i)]


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