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WB JEE Medical WB JEE Medical Solved Paper-2006

  • question_answer
    The half-life of a radio-isotope is 4 h. If initialmass of the isotope was 200 g, then massremaining after 24 h will be :

    A)  1.042g                                 

    B)  2.084 g

    C)   3.125 g                               

    D)  4.167 g

    Correct Answer: C

    Solution :

                     \[M={{M}_{}}_{0}{{\left( \frac{1}{2} \right)}^{t/{{t}_{1/2}}}}\] \[\therefore \]  \[M=200{{\left( \frac{1}{2} \right)}^{24/4}}\] \[=200{{\left( \frac{1}{2} \right)}^{6}}\] \[=\frac{200}{64}=3.125\,g\]


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