A) \[{{(C{{H}_{3}})}_{4}}{{N}^{+}}{{I}^{-}}\]
B) \[C{{H}_{3}}OC{{H}_{3}}\]
C) \[{{(C{{H}_{3}})}_{3}}{{S}^{+}}{{I}^{-}}\]
D) \[{{(C{{H}_{3}})}_{3}}Cl\]
Correct Answer: A
Solution :
\[{{(C{{H}_{3}})}_{4}}{{N}^{+}}{{I}^{-}}+NaOH\to {{(C{{H}_{3}})}_{4}}{{N}^{+}}O{{H}^{-}}\] \[+NaI\] \[{{(C{{H}_{3}})}_{4}}{{N}^{+}}O{{H}^{-}}\xrightarrow{\Delta }{{(C{{H}_{3}})}_{3}}N\underset{\text{methanol}}{\mathop{+C{{H}_{3}}OH}}\,\]
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