A) \[13.6\text{ }eV\]
B) \[54.4\text{ }eV\]
C) \[122.4\text{ }eV\]
D) Zero
Correct Answer: B
Solution :
lonisation energy of \[H{{e}^{+}}=13.6\times {{Z}^{2}}\,eV\] \[=13.6\times {{(2)}^{2}}eV\] \[=13.6\times 4\,eV=54.4\,eV\]You need to login to perform this action.
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