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WB JEE Medical WB JEE Medical Solved Paper-2007

  • question_answer
    The number of \[\alpha \] and \[\beta \] particles emitted in  nuclear  reaction  \[{{\,}_{90}}T{{h}^{228}}\to {{\,}_{83}}B{{i}^{212}}\]  are respectively

    A)  4, 1                                       

    B)  3, 7

    C)  8, 1                                       

    D)  4, 7

    Correct Answer: A

    Solution :

                     Number of \[\alpha \] particle \[=\frac{difference\,of\,mass\,number}{4}\] \[=\frac{228-212}{4}=\frac{16}{4}=4\] Number of \[\beta \] particle \[=2\times \alpha -\] (difference of atomic numbers) \[=2\times 4-(90-83)=2\times 4-7=1\]


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