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WB JEE Medical WB JEE Medical Solved Paper-2007

  • question_answer
    When 10g of 90% pure lime stone is heated completely, the volume (in litres) of \[\text{C}{{\text{O}}_{\text{2}}}\]is liberated at STP is

    A)  22.4                                      

    B)  2.24

    C)  20.16                                   

    D)  2.016

    Correct Answer: D

    Solution :

                     Amount of pure lime stone \[(CaC{{O}_{3}})\] is 10g of  90% sample \[=\frac{90}{100}\times 10=9\,g\] Molecular mass of \[CaC{{O}_{3}}=100\] Thus, 100 g of lime stone gives 22.4 L of \[C{{O}_{2}}\] at STP 9 g of lime stone gives 22.4 L of \[C{{O}_{2}}\] at STP. 9 g of lime stone will give\[=\frac{22.4}{100}\times 9=2.016\,L\]


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