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  3. WB JEE Medical

WB JEE Medical WB JEE Medical Solved Paper-2007

  • question_answer
    In the electric circuit shown each cell has an emf of 2 V and internal resistance of \[1\Omega .\]The external resistance is \[2\Omega .\] The value of the current \[\text{I}\] is (in amperes)

    A)  2                                            

    B)  1.25

    C)  0.4                                        

    D)  1.2

    Correct Answer: D

    Solution :

                     \[\text{Current}\,\text{=}\frac{\text{net}\,\text{emf}}{\text{net}\,\text{resistance}}\]or  \[I=\frac{2+2+2}{1+1+1+2}=\frac{6}{5}=1.2\,A\]


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