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WB JEE Medical WB JEE Medical Solved Paper-2007

  • question_answer
    If molecular weight of \[KMn{{O}_{4}}\] is M, then its equivalent weight in acidic medium would be

    A)  \[~M\]                                

    B)  \[\frac{M}{2}\]

    C)  \[\frac{M}{5}\]                                

    D)  \[\frac{M}{3}\]

    Correct Answer: C

    Solution :

                     \[MnO_{4}^{-}+8{{H}^{+}}+5{{e}^{-}}\to M{{n}^{2+}}4{{H}_{2}}O\] Gain electrons = 5 Molecular weight = M \[Equivalent\,weight\,=\frac{molecular\,weight}{gain\,electron}=\frac{M}{5}\]


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