A) 30%
B) 6%
C) 3%
D) 10%
Correct Answer: B
Solution :
20 volumes of \[{{H}_{2}}{{O}_{2}}\]means 20 L of oxygen is obtained at STP by the decomposition of 1L \[{{H}_{2}}{{O}_{2}}\]solution \[\underset{\begin{smallmatrix} 2\,mol \\ 68\,g \end{smallmatrix}}{\mathop{2{{H}_{2}}{{O}_{2}}}}\,\xrightarrow{{}}2{{H}_{2}}O+\underset{\begin{smallmatrix} 1\,mol \\ 22.4\,L \\ at\,STP \end{smallmatrix}}{\mathop{{{O}_{2}}}}\,\] 22.4 L oxygen is obtained from \[=\frac{68}{22.4}\times 20=60.7g\,{{H}_{2}}{{O}_{2}}\] \[\therefore \] 1000 mL of\[{{H}_{2}}{{O}_{2}}\] solution contains 60.7g \[{{H}_{2}}{{O}_{2}}\] \[100\,mL(\approx \,100\,g)\]solution contains\[\frac{60.7}{1000}\times 100\] \[\therefore \] Strength of \[{{H}_{2}}{{O}_{2}}\]solution \[=6.07g\,{{H}_{2}}{{O}_{2}}=6.07%\]
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