A) \[C{{l}_{2}}\]
B) \[N{{a}_{2}}C{{O}_{3}}\]
C) \[Ca(OCl)Cl\]
D) \[{{K}_{2}}C{{O}_{3}}\]
Correct Answer: B
Solution :
Permanent hardness is removed by precipitating carbonates of \[C{{a}^{2+}}\] and \[M{{g}^{2+}}\] \[CaC{{l}_{2}}+N{{a}_{2}}C{{O}_{3}}\to CaC{{O}_{3}}\downarrow +2\,NaCl\]
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