A) \[{{N}_{2}}\]and \[NC{{l}_{3}}\]
B) \[{{N}_{2}}\]and \[HCl\]
C) \[{{N}_{2}}\] and \[N{{H}_{4}}Cl\]
D) \[NC{{l}_{3}}\]and \[HCl\]
Correct Answer: D
Solution :
Ammonia on reaction with excess of chlorine gives nitrogen trichloride \[N{{H}_{3}}+\underset{excess}{\mathop{3C{{l}_{2}}}}\,\to NC{{l}_{3}}+3HCl\]
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