WB JEE Medical WB JEE Medical Solved Paper-2007

  • question_answer
    Reaction of \[\text{HN}{{\text{O}}_{\text{3}}}\]with I, S, P and C gives respectively

    A)  \[~HI{{O}_{3}},{{H}_{2}}S{{O}_{4}},{{H}_{3}}P{{O}_{4}}\]and \[C{{O}_{2}}\]

    B)  \[HI{{O}_{3}},\text{ }{{H}_{2}}S{{O}_{4}},\text{ }{{H}_{3}}P{{O}_{3}},\]and\[C{{O}_{2}}\]

    C)  \[HI{{O}_{2}},\text{ }{{H}_{2}}S{{O}_{4}},\text{ }{{H}_{3}}P{{O}_{4}},\]and CO

    D)  \[{{I}_{2}}{{O}_{5}},S{{O}_{2}},{{P}_{2}}O,\]and \[C{{O}_{2}}\]

    Correct Answer: A

    Solution :

                     \[{{I}_{2}}+10HN{{O}_{3}}\xrightarrow{\Delta }2HI{{O}_{3}}+10N{{O}_{2}}+4{{H}_{2}}O\] \[S+6HN{{O}_{3}}\xrightarrow{\Delta }{{H}_{2}}S{{O}_{4}}+6N{{O}_{2}}+2{{H}_{2}}O\] \[{{P}_{4}}+20HN{{O}_{3}}\xrightarrow{\Delta }4{{H}_{3}}P{{O}_{4}}+20N{{O}_{2}}\] \[+\,4{{H}_{2}}O\] \[C+4HN{{O}_{3}}\xrightarrow{\Delta }C{{O}_{2}}+4N{{O}_{2}}+2{{H}_{2}}O\]


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