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WB JEE Medical WB JEE Medical Solved Paper-2007

  • question_answer
    Solubility of \[AgCl\] at \[20{{\,}^{o}}C\] is \[1.435\times {{10}^{-3}}g/L.\] The solubility product of \[AgCl\] is

    A)  \[1\times {{10}^{-5}}\]                 

    B)  \[1\times {{10}^{-10}}\]

    C)  \[1.435\times {{10}^{-5}}\]                        

    D)  \[108\times {{10}^{-3}}\]

    Correct Answer: B

    Solution :

                     \[AgClA{{g}^{+}}+C{{l}^{-}}\] \[{{K}_{sp}}=[A{{g}^{+}}][C{{l}^{-}}]\] (S = solubility in mol/L) \[S=\frac{1.435\times {{10}^{-3}}g/L}{143.5}=1\times {{10}^{-10}}\text{mol/L}\]


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