A) \[{{O}_{2}}\]
B) \[OC{{l}^{-}}\]
C) \[C{{l}_{2}}\]
D) \[C{{l}^{-}}\]
Correct Answer: C
Solution :
Bleaching action of bleaching powder is due to \[C{{l}_{2}},\]it liberate with dilute acids or even \[C{{O}_{2}}.\] \[CaOC{{l}_{2}}+C{{O}_{2}}\to CaC{{O}_{3}}+C{{l}_{2}}\]
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