A) 45
B) 182
C) 187
D) 192
Correct Answer: A
Solution :
\[\omega ={{\omega }_{0}}+\alpha \,t\] \[\Rightarrow \] \[\omega =0+\alpha \,t\] \[\Rightarrow \] \[\alpha =\frac{15}{0.270}\,rad/{{s}^{2}}\] Now, \[a=r,\,\alpha =0.81\times \frac{15}{0.270}=45\,m{{s}^{-2}}\]You need to login to perform this action.
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