A) 1: 2
B) 2 :1
C) 1 : 4
D) 4 : 1
Correct Answer: D
Solution :
Horizontal range, \[R=\frac{{{u}^{2}}\sin 2\times 45}{g}=\frac{{{u}^{2}}}{g}\] Maximum height, \[h=\frac{h{{u}^{2}}{{\sin }^{2}}45}{2g}\] \[=\frac{{{u}^{2}}}{4g}\] \[\frac{R}{h}=\frac{4}{1}\]You need to login to perform this action.
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