A) \[HCl\]
B) \[{{H}_{2}}S{{O}_{4}}\]
C) \[{{H}_{2}}O\]
D) \[N{{H}_{3}}\]
Correct Answer: C
Solution :
Water can behave as an acid as well as base. \[HCl+\underset{base}{\mathop{{{H}_{2}}O}}\,{{H}_{3}}{{O}^{+}}+C{{l}^{-}}\] \[N{{H}_{3}}+\underset{acid}{\mathop{{{H}_{2}}O}}\,NH_{4}^{+}+O{{H}^{-}}\]
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