A) \[2.03V\]
B) \[-2.03V\]
C) \[+2.71V\]
D) \[-2.71V\]
Correct Answer: C
Solution :
\[Mg\to M{{g}^{2+}}+2{{e}^{-}}\] (at anode) \[C{{u}^{2+}}+2{{e}^{-}}\to Cu\] (at cathode) \[{{E}_{cell}}=E_{cathode}^{o}-E_{anode}^{o}\] \[=+0.34-(-2.37)\] \[=+2.71\,V\]You need to login to perform this action.
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