A) an acetal
B) an aldol
C) mesitylene
D) propionaldehyde
Correct Answer: B
Solution :
The self condensation of acetaldehyde in presence of dilute alkalies is called aldol condensation. \[C{{H}_{3}}-\overset{H}{\mathop{\overset{|}{\mathop{C}}\,}}\,=O+HC{{H}_{2}}-\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,-H\] \[\xrightarrow{dil\,NaOH}C{{H}_{3}}-\underset{aldol}{\mathop{\underset{OH}{\overset{H}{\mathop{\underset{|}{\overset{|}{\mathop{C}}}\,}}}\,}}\,-C{{H}_{2}}-\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,-H\]
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