A) alcohol
B) alkyl cyanides
C) alkanones
D) acid chlorides
Correct Answer: B
Solution :
Stephens reduction? Aldehyde can prepared from alkyl cyanides, eg, \[C{{H}_{3}}-C\equiv N+2[H]\xrightarrow[ether]{SnC{{l}_{2}}/HCl}\] \[C{{H}_{3}}-C\underset{\downarrow {{H}_{2}}O/{{H}^{+}}}{\mathop{H=NH.HCl}}\,\] \[\underset{\text{acetaldehyde}}{\mathop{C{{H}_{3}}CHO}}\,\,+N{{H}_{4}}Cl\]
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