A) \[C{{l}_{2}}O\]
B) \[Cl{{O}_{2}}\]
C) \[C{{l}_{2}}{{O}_{7}}\]
D) \[C{{l}_{2}}{{O}_{6}}\]
Correct Answer: B
Solution :
A species with one or more unpaired electron is paramagnetic. Number of valence electrons in \[C{{l}_{2}}O\] \[=7\times 2+6=20\] (even) Number of valence electrons in \[Cl{{O}_{2}}\] \[=7+6\times 2=19\] (odd) Number of valence electrons in \[C{{l}_{2}}{{O}_{7}}\] \[=7\times 2+6\times 7=56\] (even) Number of valence electrons in \[C{{l}_{2}}{{O}_{6}}\] \[=7\times 2+6\times 6=50\] (even) Thus, \[Cl{{O}_{2}}\]is paramagnetic due to the odd electron.
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