A) \[C{{H}_{2}}ClCOOH\]
B) \[CHC{{l}_{2}}COOH\]
C) \[C{{H}_{3}}COCl\]
D) \[C{{H}_{3}}COOCl\]
Correct Answer: C
Solution :
Acetic acid reacts with \[\text{PC}{{\text{l}}_{5}}\] to form aeetyl chloride. \[\underset{\text{acetic}\,\text{acid}}{\mathop{C{{H}_{3}}COOH}}\,+PC{{l}_{5}}\to \underset{\text{acetyl}\,\text{chloride}}{\mathop{C{{H}_{3}}COCl}}\,\,+POC{{l}_{3}}+HCl\]
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