question_answer

Oxidation-number of sulphur in Caros acid is :

A)  + 6                                        

B)  + 4

C)  + 8                                        

D)  + 7

Correct Answer: A

Solution :

                 Caros acid is \[{{\text{H}}_{\text{2}}}\text{S}{{\text{O}}_{\text{5}}}\text{.}\]It has a peroxide linkage, so, oxidation of S is Let the oxidation state of S is \[x\] \[{{H}_{2}}S{{O}_{5}}\] (one peroxide bond) \[+2+x+3(-2)+1(-2)=0\] \[2+x-6-2=0\] \[x-6=0\] \[x=6\]