WB JEE Medical WB JEE Medical Solved Paper-2007

  • question_answer
    An electron enters uniform electric field maintained by parallel plates and of value \[\text{EV}{{\text{m}}^{-1}}\] with a velocity \[\text{v}\,\text{m}{{\text{s}}^{-1}},\] the plates are separated by a distance d metre, then acceleration of the electron in the field is

    A)  \[\frac{Ee}{m}\]                                             

    B)  \[\frac{-Ee}{m}\]

    C)  \[\frac{Ed}{m}\]                                             

    D)  \[Ee\frac{d}{m}\]

    Correct Answer: A

    Solution :

                     \[F=eE\] Therefore, acceleration in electron due to force F \[a=\frac{F}{m}=\frac{eE}{m}\]


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