question_answer

The map distance between the genes A and B is 3 units, between B and C is 10 units and between C and A is 7 units. The order of the genes in a linkage map constructed on the above data would perhaps be

A)  A, B, C                                 

B)  A, C, B

C)  B, C, A                                 

D)  B, A, C

Correct Answer: D

Solution :

                From the recombination frequencies between different genes A, B and C, it is clear that distance between A and B genes is 3 units, between B and C is 10 units and C and A is 7 units. Hence, linear order of genes on chromosomes is