A) 0.5 of original amount
B) 0.25 of original amount
C) 0.125 of original amount
D) 0.0625 of original amount
Correct Answer: B
Solution :
\[N={{N}_{0}}\times {{\left( \frac{1}{2} \right)}^{11400/5700}}\] \[={{N}_{0}}{{\left( \frac{1}{2} \right)}^{2}}=0.25{{N}_{0}}\]
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