A) \[[{{M}^{2}}{{L}^{2}}T]\]
B) \[[M{{L}^{2}}T]\]
C) \[[M{{L}^{2}}{{T}^{-2}}]\]
D) \[[M{{L}^{2}}{{T}^{-1}}]\]
Correct Answer: C
Solution :
\[KE=\frac{1}{2}m{{v}^{2}}\] \[\therefore \] \[[KE]=[M]{{[L{{T}^{-1}}]}^{2}}=[M{{L}^{2}}{{T}^{-2}}]\]
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