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  3. WB JEE Medical

WB JEE Medical WB JEE Medical Solved Paper-2007

  • question_answer
    An aeroplane is flying horizontally with a velocity of 600 km/h and at a height of 1960 m. When it is vertically above a point A on the ground a bomb is released from it. The bomb strikes the ground at point B. The distance AB is

    A)  1200m                                 

    B)  0.33km

    C)  333.3km                             

    D)  3.33km

    Correct Answer: D

    Solution :

                     \[h=\frac{1}{2}g{{t}^{2}}\Rightarrow t=\sqrt{\frac{2\times 1960}{9.8}}=20\,s\] \[\therefore \]  \[s=AB=ut=600\times \frac{20}{60\times 60}\]                 \[=3.33\,\text{km}\]


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