A) \[4\,m{{s}^{-1}}\]
B) \[6\,m{{s}^{-1}}\]
C) \[10\,m{{s}^{-1}}\]
D) \[12\,m{{s}^{-1}}\]
Correct Answer: B
Solution :
\[{{m}_{1}}{{u}_{1}}+{{m}_{2}}{{u}_{2}}=({{m}_{1}}+{{m}_{2}})v\] \[\Rightarrow \] \[10\times {{u}_{1}}+5\times 0=(10+5)\times \] \[\Rightarrow \] \[{{u}_{1}}=\frac{15\times 4}{10}=6\,m{{s}^{-1}}\]
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