A) same as the initial value
B) twice the initial value
C) thrice the initial value
D) half of its initial value
Correct Answer: B
Solution :
\[K\propto {{p}^{2}}\] \[\Rightarrow \] \[\frac{{{p}_{2}}}{{{p}_{1}}}=\sqrt{\frac{{{K}_{2}}}{{{K}_{1}}}}=\sqrt{4}\] \[\Rightarrow \] \[{{p}_{2}}=2{{p}_{1}}\]
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