WB JEE Medical WB JEE Medical Solved Paper-2007

  • question_answer
    From the top of tower, a stone is thrown up. It reaches the ground in \[{{t}_{1}}\]second. A second stone thrown down-with the same speed reaches the ground in \[{{t}_{2}}\]second. A third stone released from rest reaches the ground in \[{{t}_{3}}\]second. Then

    A)  \[{{t}_{3}}=\frac{({{t}_{1}}+{{t}_{2}})}{2}\]                           

    B)  \[{{t}_{3}}=\sqrt{{{t}_{1}}{{t}_{2}}}\]

    C)  \[\frac{1}{{{t}_{3}}}=\frac{1}{{{t}_{1}}}-\frac{1}{{{t}_{2}}}\]                          

    D)  \[t_{3}^{2}=t_{2}^{2}-t_{1}^{2}\]

    Correct Answer: B

    Solution :

                     Not Avaibalie


You need to login to perform this action.
You will be redirected in 3 sec spinner