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WB JEE Medical WB JEE Medical Solved Paper-2007

  • question_answer
    An object is projected at an angle of \[\text{4}{{\text{5}}^{\text{o}}}\] with the horizontal. The horizontal range and maximum height reached will be in the ratio :

    A)  1: 2                                       

    B)  2 :1

    C)  1 : 4                                      

    D)  4 : 1

    Correct Answer: D

    Solution :

                     Horizontal range, \[R=\frac{{{u}^{2}}\sin 2\times 45}{g}=\frac{{{u}^{2}}}{g}\] Maximum height, \[h=\frac{h{{u}^{2}}{{\sin }^{2}}45}{2g}\] \[=\frac{{{u}^{2}}}{4g}\] \[\frac{R}{h}=\frac{4}{1}\]


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