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WB JEE Medical WB JEE Medical Solved Paper-2007

  • question_answer
    A pipe open at both the ends produces a note of fundamental frequency \[{{f}_{1}}.\] When the pipe is 3 kept with \[\frac{3}{4}\text{th}\] of its length in water, it produces 4 a note of fundamental frequency \[{{f}_{2}}.\] The ratio of\[\frac{{{f}_{1}}}{{{f}_{2}}}\] is

    A)  \[\frac{4}{3}\]                                  

    B)  \[\frac{3}{4}\]

    C)  2                                            

    D)  \[\frac{1}{2}\]

    Correct Answer: D

    Solution :

                     Accordingly \[{{f}_{1}}=\frac{v}{2l}\]                                                                ?(i) and \[{{f}_{2}}=\frac{v}{4l/4}=\frac{v}{l}\]                            ?(ii) Hence,  \[\frac{{{f}_{1}}}{{{f}_{2}}}=\frac{1}{2}\]


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