WB JEE Medical WB JEE Medical Solved Paper-2007

  • question_answer
    Three identical spheres, each of mass 1kg are kept as shown in figure below, touching each other, with their centres on a straight line. If their centres are marked P, Q, R respectively, the distance of centre of mass of the system from P is

    A) (a ) \[\frac{PQ+PR+QR}{3}\]       

    B)  \[\frac{PQ+PR}{3}\]

    C)  \[\frac{PQ+QR}{3}\]                      

    D)  \[\frac{PR+QR}{3}\]

    Correct Answer: B

    Solution :

                     \[{{r}_{1}}=0,\,{{r}_{2}}=PQ,{{r}_{3}}=PR\] Distance of centre of mass form P is \[r=\frac{{{r}_{1}}+{{r}_{2}}+{{r}_{3}}}{3}=\frac{0+PQ+PR}{3}=\frac{PQ+PR}{3}\]


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