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WB JEE Medical WB JEE Medical Solved Paper-2007

  • question_answer
    Two identical solid copper spheres of radius R are placed in contact with each other. The gravitational attraction between them is proportional to

    A)  \[{{R}^{2}}\]                                     

    B)  \[{{R}^{-2}}\]

    C)  \[{{R}^{4}}\]                                     

    D)  \[{{R}^{-4}}\]

    Correct Answer: C

    Solution :

                     \[F=\frac{GMM}{{{R}^{2}}}\] \[=\frac{G\left( \frac{4}{3}\pi {{R}^{3}}\rho  \right)\left( \frac{4}{3}\pi {{R}^{3}}\rho  \right)}{{{R}^{2}}}\]                              \[\therefore \]  \[F\propto {{R}^{4}}\]


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